Math.Min |
Minimum |
|---|---|
| VB .NET (Visual Basic .NET) | System |
Syntaxe
| Function Math.Min(val1 As Byte, val2 As Byte) As Byte |
| Function Math.Min(val1 As Decimal, val2 As Decimal) As Decimal |
| Function Math.Min(val1 As Double, val2 As Double) As Double |
| Function Math.Min(val1 As Short, val2 As Short) As Short |
| Function Math.Min(val1 As Integer, val2 As Integer) As Integer |
| Function Math.Min(val1 As Long, val2 As Long) As Long |
| Function Math.Min(val1 As SByte, val2 As SByte) As SByte |
| Function Math.Min(val1 As Single, val2 As Single) As Single |
| Function Math.Min(val1 As UShort, val2 As UShort) As UShort |
| Function Math.Min(val1 As ULong, val2 As ULong) As ULong |
Paramètres
| Nom | Description |
|---|---|
| val1, val2 | Ces paramètres permettent d'indiquer l'expression contenant le nombre à comparer. |
Description
Ces méthodes retournent la plus petite valeur entre les deux paramètres.
Exemple
Voici un exemple permet d'afficher les plus petites valeurs :
- Module Module1
-
- Sub Main()
- Console.WriteLine("MIN(5,-18)=" & Math.Min(5, -18))
- Console.WriteLine("MIN(0.25,0.115)=" & Math.Min(0.25, 0.115))
- Console.WriteLine("MIN(1,2)=" & Math.Min(1, 2))
- Console.WriteLine("MIN(5,4)=" & Math.Min(5, 4))
- Console.WriteLine("MIN(24,34)=" & Math.Min(24, 34))
- End Sub
-
- End Module
on obtiendra le résultat suivant :
MIN(5,-18)=-18MIN(0.25,0.115)=0,115
MIN(1,2)=1
MIN(5,4)=4
MIN(24,34)=24
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Dernière mise à jour : Dimanche, le 9 novembre 2014